Encyclopedia … combined with a great Buyer's Guide!

Acceptance Angle in Fiber Optics

Definition: the maximum incidence angle of a light ray which can be used for injecting light into a fiber core or waveguide

German: Akzeptanzwinkel in der Faseroptik

Category: fiber optics and waveguidesfiber optics and waveguides


Cite the article using its DOI: https://doi.org/10.61835/wg6

Get citation code: Endnote (RIS) BibTex plain textHTML

The acceptance angle of an optical fiber is defined based on a purely geometrical consideration (ray optics): it is the maximum angle of a ray (against the fiber axis) hitting the fiber core which allows the incident light to be guided by the core. The sine of that acceptable angle (assuming an incident ray in air or vacuum) is called the numerical aperture, and it is essentially determined by the refractive index contrast between core and cladding of the fiber, assuming that the incident beam comes from air or vacuum:

$${\theta _{{\rm{acc}}}} = \arcsin \left( {\frac{1}{{{n_0}}}\sqrt {{n_{{\rm{co}}}}^2 - {n_{{\rm{cl}}}}^{\rm{2}}} } \right)$$

Here, <$n_\textrm{co}$> and <$n_\textrm{cl}$> are the refractive indices of core and cladding, respectively, and <$n_0$> is the refractive index of the medium around the fiber, which is close to 1 in the case of air.

acceptance angle of a fiber
Figure 1: An incident light ray is first refracted and then undergoes total internal reflection at the core–cladding interface. However, that works only if the incidence angle is not too large.

For larger incidence angles, there is no total internal reflection, and much of the incident light will not be reflected at the core–cladding boundary. It will thus get into the cladding and will then usually experience strong propagation losses particularly at the outer part of the cladding.

Calculating the acceptance angle of a fiber

Core index:
Cladding index:
Index of input medium:
Numerical aperture:calc
Acceptance angle:calc

Enter input values with units, where appropriate. After you have modified some values, click a “calc” button to recalculate the field left of it.

Further Remarks

For a strongly multimode waveguide, the acceptance angle can be used to estimate the maximum input angle of a laser beam for which a high launch efficiency of the waveguide can be achieved. For single-mode fibers, however, this rule does not hold, as explained in the following.

case study numerical aperture

Case Studies

Case Study: The Numerical Aperture of a Fiber: a Strict Limit for the Acceptance Angle?

The requirement of total internal reflection would seem to set a strict limit for the angular distributions of fiber modes. However, some modes are found to exceed that limit significantly. We investigate that in detail for single-mode, few-mode and multimode fibers.

The concept of ray optics (geometrical optics) is not fully appropriate for describing the operation details of optical fibers because wave aspects are important – particularly for fibers with small core such as single-mode fibers, while the approximation is more appropriate for large-core multimode fibers. A real light beam (for example, a laser beam) is not well resembled by a ray, since it inevitably has both a finite beam radius and a finite beam divergence. Therefore, there is in reality not a well-defined transition between guidance and non-guidance, when a beam angle is varied; the launch efficiency varies gradually. Only in the limit of a highly multimode waveguide, such estimates based on geometrical optics become reasonably accurate.

Note that the term acceptance angle also plays a role in nonlinear optics – see the article on critical phase matching.

More to Learn

Case studies:

Encyclopedia articles:

Questions and Comments from Users


If a fiber is immersed in water, how does that change its acceptance angle?

The author's answer:

The acceptance angle is substantially reduced, as you can calculate with the formula given above.


How do you calculate the maximum acceptance angle in water and in air for the case of an uncladded fiber?

The author's answer:

If you just mean an optically homogeneous fiber, not having core and cladding, and you can regard the surrounding air or water as your cladding. Just use the calculator above.


Does the angle of exit of light from a step-index multimode fiber tell you anything about the angle of entry?

The author's answer:

Theoretically, that angle should be preserved, but any bending of the fiber or imperfections of the fiber structure may easily spoil that relation.


Why is the acceptance angle not dependent on the diameter? Isn't there any diffraction effects? Or doesn't the divergence angle of the Gaussian beam come into play?

The author's answer:

The acceptance angle is based on purely geometric reasoning (geometrical optics). Diffraction is not considered in that context. Within wave optics, where diffraction can be considered, there is no precisely defined acceptance angle.


Does the acceptance angle depend on the wavelength of light?

The author's answer:

Only weakly through the refractive index.


Is the maximum acceptance angle equal to the maximum possible angle of the output beam of the fiber?

The author's answer:

Geometrically yes, but such a light beam is of course not a realistic description of what can come out of such a fiber – particularly if it is a single-mode or few-mode fiber.


Is the acceptance angle the same as the field of view of the fiber?

The author's answer:

The term field of view is a quantity defined for optical systems, often for imaging systems, and should not be applied to an optical fiber.


For optimum coupling of a focused light beam in a multimode fiber (with focal spot size < fiber core diameter), what should be the relationship between the cone angle of the focused beam and acceptance angle of the fiber, i.e., by what percentage should the cone angle be less than the acceptance angle?

The author's answer:

That depends on what exactly you mean with “cone angle”. Ideally, the whole angular distribution would be within the acceptance angle according to the NA.


If you have a cladding and core refractive index so large that NA > 1 so that sin(acceptance angle) does not compute, what does this mean physically for the acceptance angle? An example would be a SiO2 cladding with <$n$> = 1.45 and SiNx core with <$n$> = 2 (at 850 nm).

The author's answer:

This means that even for the largest possible incidence angles of rays (in air!) you will get total internal reflection at the core–cladding boundary.

Here you can submit questions and comments. As far as they get accepted by the author, they will appear above this paragraph together with the author’s answer. The author will decide on acceptance based on certain criteria. Essentially, the issue must be of sufficiently broad interest.

Please do not enter personal data here. (See also our privacy declaration.) If you wish to receive personal feedback or consultancy from the author, please contact him, e.g. via e-mail.

Spam check:

By submitting the information, you give your consent to the potential publication of your inputs on our website according to our rules. (If you later retract your consent, we will delete those inputs.) As your inputs are first reviewed by the author, they may be published with some delay.


Share this with your network:

Follow our specific LinkedIn pages for more insights and updates: