ABCD is a rectangle whose three vertices are B (4, 0), C(4, 3) and D(0,3). The length of one of its diagonals is

(A) 5

(B) 4

(C) 3

(D) 25

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#### Solution

Correct answer: A

We see that AB = 4 units and BC = 3 units

Using Pythagoras theorem

AC^{2}= AB^{2}+ BC^{2}

=4^{2} + 3^{2}

AC^{ 2} =25

Thus AC = 5 units

Hence length of the diagonal of the rectangle is 5 units

Concept: Right-angled Triangles and Pythagoras Property

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